Momentum and CollisionHard
Question
A cylindrical container of radius ′R′ and height ′h′ is completely filled with a liquid, Two horizontal L shaped pipes of small cross-section area ′a′ are connected to the cylinder as shown in the figure. Now the two pipes are opened and fluid starts coming out of the pipes horizontally in opposite directions. Then the torque due to ejected liquid on the system is -
Options
A.4 aghρR
B.8 aghρR
C.2 aghρR
D.none of these
Solution
Velocity of efflux of water
=
Force due to ejected water
v = ρ(av)v = ρav2
Torque of these forces about central line
= F × 2R + F × 2R = 4ρav2 × R = 4ρaghR
=
Force due to ejected water
v = ρ(av)v = ρav2Torque of these forces about central line
= F × 2R + F × 2R = 4ρav2 × R = 4ρaghR
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