Momentum and CollisionHard
Question
A cylindrical container of radius ′R′ and height ′h′ is completely filled with a liquid, Two horizontal L shaped pipes of small cross-section area ′a′ are connected to the cylinder as shown in the figure. Now the two pipes are opened and fluid starts coming out of the pipes horizontally in opposite directions. Then the torque due to ejected liquid on the system is -
Options
A.4 aghρR
B.8 aghρR
C.2 aghρR
D.none of these
Solution
Velocity of efflux of water
=
Force due to ejected water
v = ρ(av)v = ρav2
Torque of these forces about central line
= F × 2R + F × 2R = 4ρav2 × R = 4ρaghR
=
Force due to ejected water
v = ρ(av)v = ρav2Torque of these forces about central line
= F × 2R + F × 2R = 4ρav2 × R = 4ρaghR
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
Two particles A and B initially at rest, move towards each other the mutual force of attraction. At the instant when the...A mass ′m′ moves with a velocity ′v′ and collides inelastically with another identical mass. Aft...Considering a system having two masses m1 and m2 which first masses is pushed towards centre of mass by a distance a, th...In the given figure, the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is :...A cubical block of wood of side 10 cm floats at the interface between oil and water as shown in the figure with its lowe...