Ionic EquilibriumHard

Question

The solubility of  CaF2 (Ksp = 3.4 × 10-11) in 0.1 M solution of NaF would be

Options

A.3.4 × 10-12 M
B.3.4 × 10-10 M
C.3.4 × 10-9 M
D.3.4 × 10-13 M

Solution

(a)     NaF     Na+    +    F-
        0.1        0.1        0.1
        CaF2     Ca2+    +    2F-
                        (2x + 0.1) ≈  0.1
Ksp = x (0.1)2  = 3.4 × 10-11     x = 3.4 × 10-9

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