Ionic EquilibriumHard
Question
The sodium salt of a certain weak monobasic organic acid is hydrolysed to an extent of 3% in its 0.1M solution at 25oC. Given that the ionic product of water is 10-14 at this temperature, what is the dissociation constant of the acid?
Options
A.≈ 1 × 10-10
B.≈ 1 × 10-9
C.3.33 × 10-9
D.3.33 × 10-10
Solution
h = .03 C = 0.1 M
Kh = Ch2 = 9 × 10-5
Kh =
= 9 × 10-5 ⇒ Ka = 
= 1.11 × 10-10 ≈ 1 × 10-10
Kh = Ch2 = 9 × 10-5
Kh =
= 9 × 10-5 ⇒ Ka = = 1.11 × 10-10 ≈ 1 × 10-10Create a free account to view solution
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