Ionic EquilibriumHard
Question
How many moles of NaOH must be removed from one litre of aqueous solution to change its pH from
12 to 11 ?
12 to 11 ?
Options
A.0.009
B.0.01
C.0.02
D.0.1
Solution
Inital Final
pH = 12 pH = 11
[H+] = 10-12 M [H+] = 10-11 M
[OH-] = 10-2 M [OH-] = 10-3 M
Inital No. of mole of OH- = 10-2 Final No. of mole of OH- = 10-3
So no. of mole of OH- removed = [.01 - 0.001] = 0.009
pH = 12 pH = 11
[H+] = 10-12 M [H+] = 10-11 M
[OH-] = 10-2 M [OH-] = 10-3 M
Inital No. of mole of OH- = 10-2 Final No. of mole of OH- = 10-3
So no. of mole of OH- removed = [.01 - 0.001] = 0.009
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