Ionic EquilibriumHard
Question
How many moles of NaOH must be removed from one litre of aqueous solution to change its pH from
12 to 11 ?
12 to 11 ?
Options
A.0.009
B.0.01
C.0.02
D.0.1
Solution
Inital Final
pH = 12 pH = 11
[H+] = 10-12 M [H+] = 10-11 M
[OH-] = 10-2 M [OH-] = 10-3 M
Inital No. of mole of OH- = 10-2 Final No. of mole of OH- = 10-3
So no. of mole of OH- removed = [.01 - 0.001] = 0.009
pH = 12 pH = 11
[H+] = 10-12 M [H+] = 10-11 M
[OH-] = 10-2 M [OH-] = 10-3 M
Inital No. of mole of OH- = 10-2 Final No. of mole of OH- = 10-3
So no. of mole of OH- removed = [.01 - 0.001] = 0.009
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
The volume of the water needed to dissolve 1 g of BaSO4 (KSP = 1.1 × 10-10) at 25oC is:...At 25oC, the solubility product of Mg(OH)2 is 1.0 × 10-11. At what pH, will Mg2+ ion start precipitating in the for...A certain sample of rainwater gives a yellow colour with methyl red [pH range 4.2 (red) – 6.2 (yellow)] and a yellow col...The existence of a substance of a substance in more than one solid modifications is known as...Equimolar solutions of the following substances were prepared separately. Which one of these will record the highest pH ...