Ionic EquilibriumHard
Question
Kw of H2O at 373 K is 1 × 10-12. Identify which of the following is/are correct.
Options
A.pKw of H2O is 12
B.pH of H2O is 6
C.H2O is neutral
D.H2O is acidic
Solution
pKw = - logKw = - log 1 × 10-12 = 12.
Kw = [H+][OH-] = 10-12.
[H+] = [OH-]
⇒ [H+]2 = 10-12 ; [H+] = 10-6 ; pH = - log [H+] = - log 10-6 = 6.
H2O is neutral because [H+] = [OH-] at 373 K even when pH = 6.
(D) is not correct at 373 K. Water cannot become acidic.
Kw = [H+][OH-] = 10-12.
[H+] = [OH-]
⇒ [H+]2 = 10-12 ; [H+] = 10-6 ; pH = - log [H+] = - log 10-6 = 6.
H2O is neutral because [H+] = [OH-] at 373 K even when pH = 6.
(D) is not correct at 373 K. Water cannot become acidic.
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Among the following acids which has the lowest pKa value?...What would be the pH of an ammonia solution if the pH of acetic acid solution of same strength is 3.2? The dissociation ...HCHO reacts with CH3MgI followed by hydrolysis to give :-...The lassaigne′s extract is boiled with conc. HNO3 while testing for the hologens by doing so it :-...A solution contains a mixture of Ag+ (0.10 M) and Hg22+ (0.10 M), which are to be separated by selective precipitation. ...