GravitationHard
Question
Escape velocity of a body from the surface of Earth is 11.2 km/sec. from the Earth surface. If the mass of Earth becomes double of its present mass and radius becomes half of its present radius, then escape velocity will become
Options
A.5.6 km/sec
B.11.2 km/sec
C.22.4 km/sec
D.44.8km/sec
Solution
ve = 
;V′e = 
ve = 2 (11.2 km/sec) = 22.4 km/sec
;V′e = ve = 2 (11.2 km/sec) = 22.4 km/sec
Create a free account to view solution
View Solution FreeMore Gravitation Questions
The value of acceleration due to gravity , at earth surface is g. Its value at the centre of the, which we assume as a s...Hubble′s law is related with...Energy required to move a body of mass m from an orbit of radius 2R to 3R is...A satellite is seen after each 8 hours over equator at a place on the Earth when its sense of rotation is opposite to th...A particle of mass M is at a distance a from surface of a thin spherical shell of equal mass and having radius a...