Sound WavesHard
Question
Sounds from two identical sources S1 and S2 reach a point P. When the sounds reach directly, and in the same phase, the intensity at P is I0. The power of S1 is now reduced by 64% and the phase difference between S1 and S2 is varied continuously. The maximum and minimum intensities recorded at P are now Imax and Imin : -
Options
A.Imax = 0.644I0
B.Imin = 0.36 I0
C.
= 16
= 16D.
Solution
Let a = initial amplitude due to S1 and S2 each.
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
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