Sound WavesHard
Question
Sounds from two identical sources S1 and S2 reach a point P. When the sounds reach directly, and in the same phase, the intensity at P is I0. The power of S1 is now reduced by 64% and the phase difference between S1 and S2 is varied continuously. The maximum and minimum intensities recorded at P are now Imax and Imin : -
Options
A.Imax = 0.644I0
B.Imin = 0.36 I0
C.
= 16
D.
Solution
Let a = initial amplitude due to S1 and S2 each.
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
Aparticle execute simple harmonic motion with an angular velocity of 3.5 rad/sec andmaximum acceleration 7.5m/ s2 .The a...Choose the CORRECT option(s) :-...The same note being played on sitar and veena differ is...A string is stretched between fixed points separated by 75 cm. It is observed to have resonant frequencies of 420 Hz and...The equation y = a sin 2π/λ (vt - x) is expression for : -...