Sound WavesHard
Question
Sounds from two identical sources S1 and S2 reach a point P. When the sounds reach directly, and in the same phase, the intensity at P is I0. The power of S1 is now reduced by 64% and the phase difference between S1 and S2 is varied continuously. The maximum and minimum intensities recorded at P are now Imax and Imin : -
Options
A.Imax = 0.644I0
B.Imin = 0.36 I0
C.
= 16
= 16D.
Solution
Let a = initial amplitude due to S1 and S2 each.
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
I0 = k(4a2), where k is a constant
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition
amax = a+ 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
A uniform wire of cross-sectional area 1 mm2 and length 60 cm made of steel (density 8000 kg/m3) is tied at both ends un...The average speed of the bob of a simple pendulum oscillating with a small amplitude A. and time period T is...The major product(s) of the following reaction is (are) -...A train is moving on a straight track with speed 20 ms−1. It is blowing its whistle at the frequency of 1000 Hz. T...Three progressive waves A, B and C are shown in figure. With respect to wave A...