Sound WavesHard
Question
A transverse wave is described by the equation y = y0sin2π (ƒt -
). The maximum particle velocity is equal to four times the wave velocity if : -
Options
A.
B.
C.λ = πy0
D.λ = 2πy0
Solution
y = y0 sin 2π
; v = y0 (2πf) cos 2π 
vmax = y02πf ; vwave = fλ
Given vmax = 4vwave
⇒ y0(2πf) = 4(fλ) ⇒
vmax = y02πf ; vwave = fλ
Given vmax = 4vwave
⇒ y0(2πf) = 4(fλ) ⇒
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