SHMHard
Question
A particle is subjected to two simple harmonic motions along x and y directions according to , x = 3 sin 100πt ; y = 4sin 100πt.
Options
A.Motion of particle will be on ellipse traversing it in clockwise direction
B.Motion of particle will be on straight line with slope 4/3
C.Motion will be harmonic motion with amplitude 5
D.Phase difference between two motions is π/s
Solution
x = 3 sin (100), y = 4 sin (100) y = 
x
⇒ motion of particle will be on a straight line with slope 4/3.
As r =
so motion of particle will be SHM with amplitude 5.
x⇒ motion of particle will be on a straight line with slope 4/3.
As r =
so motion of particle will be SHM with amplitude 5.
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