SHMHard
Question
The graph shows the variation of displacement of a particle executing S.H.M with time We inference from this graph that : -
Options
A.the force is zero at time 
B.the velocity is maximum at time 
C.the acceleration is maximum at time T
D.the P.E. is equal to half of total energy at time
Solution
For (A) : at t = 
, particle at extreme position
∵ a = - ω2x ∴ F ≠ 0
For (B) : at t = T/2, particle at meat position
v = ωA(maximum)
For (C) : at t = T particle at mean position
⇒ a = - ω2x = 0
For (D) : at t = T / 2, particle at mean position
so x = 0 ⇒ U =
kx2 = 0
, particle at extreme position ∵ a = - ω2x ∴ F ≠ 0
For (B) : at t = T/2, particle at meat position
v = ωA(maximum)
For (C) : at t = T particle at mean position
⇒ a = - ω2x = 0
For (D) : at t = T / 2, particle at mean position
so x = 0 ⇒ U =
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