SHMHard
Question
A particle executes SHM on a line 8 cm long. Its K.E. and P.E. will equal when its distance from the mean position is : -
Options
A.4 cm
B.2 cm
C.2√2 cm
D.√2 cm
Solution
Here 
mv2 = 
kx2 ⇒ 
mω2(a2 - x2) = 
mω2x2
⇒ x =
= 2√2 m
mv2 = kx2 ⇒ mω2(a2 - x2) = mω2x2⇒ x =
= 2√2 mCreate a free account to view solution
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