Gaseous StateHard
Question
A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressure of A and B are 3.0 and 1.0 atm respectively and if C has mol. wt. of 2.0, what is the weight of C in g present in the mixture ?
Options
A.6
B.8
C.12
D.3
Solution
Pressure of Total mixture = 10 atm
PA + PB + PC = 10
3 + 1 + PC = 10 ⇒ PC = 6 atm
Total moles of mixture = 10
nA + nB + nC = 10
⇒ 
Let nA = K ⇒ nB =
nc = 
nB = 2K
⇒ K +
+ 2K = 10 ⇒ 
⇒ nC = 2K
⇒ K
= 10 K = 3, ⇒ nA = 3
nB = 1
nC = 6
∴ weight of ′C′ in mixture = 2 × 6 = 12
PA + PB + PC = 10
3 + 1 + PC = 10 ⇒ PC = 6 atm
Total moles of mixture = 10
nA + nB + nC = 10
⇒ Let nA = K ⇒ nB =
nc = nB = 2K⇒ K +
+ 2K = 10 ⇒ ⇒ nC = 2K⇒ K
= 10 K = 3, ⇒ nA = 3nB = 1
nC = 6
∴ weight of ′C′ in mixture = 2 × 6 = 12
Create a free account to view solution
View Solution FreeMore Gaseous State Questions
For the diffusion of a gas at pressure P, the rate of diffusion is expressed by:...Equal weights of methane and oxygen are mixed in an empty container at 25o C. The fraction of the total pressure exerted...The density of neon will be highest at :...Which of the following expression correctly represents the relationship between the average kinetic energy of CO and N2 ...For gaseous state which of the following is incorrect ?...