Trigonometric EquationHard
Question
If the distance of the point P (1, - 2, 1) from the plane x + 2y - 2z = α, where α > 0, is 5, then the foot of the perpendicular from P to the plane is
Options
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Solution
Distance of point (1, - 2, 1) from plane x + 2y - 2z = α is 5 ⇒ α = 10
Equation of PQ
Q ≡ (t + 1, 2t - 2, - 2t + 1) and PQ = 5 ⇒ t =
Equation of PQ
Q ≡ (t + 1, 2t - 2, - 2t + 1) and PQ = 5 ⇒ t =
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