Work, Power and EnergyHard
Question
Sample pendulums P1 and P2 have lengths l1 = 80 cm and l2 = 100 cm respectively. The bobs are of masses m1 and m2. Initially both are at rest in equilibrium position. If each of the bobs is displacement of 2 cm, the work done is W1 and W2 respectively. Then,
Options
A.W1 > W2 if m1 = m2
B.W1 < W2 if m1 = m2
C.W1 = W2 if 
D.W1 = W2 if 
Solution
With usual notation, the height through which the bob falls h = l (1 - cos) = l
since θ is small. Therefore, we can write h = 
where a = amplitude
Thus, the work w = P > E = mgh =
⇒ W ∝
since θ is small. Therefore, we can write h = where a = amplitudeThus, the work w = P > E = mgh =
⇒ W ∝Create a free account to view solution
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