Laws of MotionHard
Question
The rear side of a truck is open and a box of mass 20 kg is placed on the truck 4m away from the open end. μ = 0.15 and g = 10 m/ sec2. The truck from rest with an acceleration of 2m/sec2 on a straight road. the distance moved by the truck when box starts fall down .
Options
A.4m
B.8m
C.16m
D.32m
Solution
Acceleration of box w.r.t truck
= 2 - (0.15)(10) = 0.5ms-2.
The box will fall off at time t then from
s = ut +
at2 ; 4 = 
(0.5)t2 t = 4s
Distance traveled by truck =
(2)(4)2 = 16 m
= 2 - (0.15)(10) = 0.5ms-2.The box will fall off at time t then from
s = ut +
at2 ; 4 = (0.5)t2 t = 4s Distance traveled by truck =
(2)(4)2 = 16 mCreate a free account to view solution
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