Atomic StructureHard
Question
Which of the given statement (s) is/are false.
I Orbital angular momentum of the electron having n = 5 and having value of the azimuthal quantum number as lowest for this principle quantum number is h/π.
II If n = 3, l = 0, m = 0, for the last valence shell electron, then the possible atomic number must be 12 or 13.
III Total spin of electrons for the atom 25Mn is ± 7/2.
IV Spin magnetic moment of inert gas is 0
I Orbital angular momentum of the electron having n = 5 and having value of the azimuthal quantum number as lowest for this principle quantum number is h/π.
II If n = 3, l = 0, m = 0, for the last valence shell electron, then the possible atomic number must be 12 or 13.
III Total spin of electrons for the atom 25Mn is ± 7/2.
IV Spin magnetic moment of inert gas is 0
Options
A.I, II and III
B.II and III only
C.I and IV only
D.None of these
Solution
I : For n = 5, lmin = 0. ∴ Orbital angular momentum = 
= 0.(False)
II : Outermost electronic configuration = 3s1 or 3s2. ∴ possible atomic number = 11or 12 (False).
III : Mn25 = [Ar] 3d5 4s2. ∴ 5 unpaired electrons ∴ Total spin = ±
(False).
IV : Inert gases have no unpaired electrons. ∴ spin magnetic moment = 0 (True).
= 0.(False)II : Outermost electronic configuration = 3s1 or 3s2. ∴ possible atomic number = 11or 12 (False).
III : Mn25 = [Ar] 3d5 4s2. ∴ 5 unpaired electrons ∴ Total spin = ±
(False).IV : Inert gases have no unpaired electrons. ∴ spin magnetic moment = 0 (True).
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