Atomic StructureHard

Question

Which of the given statement (s) is/are false.
I Orbital angular momentum of the electron having n = 5 and having value of the azimuthal quantum number as lowest for this principle quantum number is h/π.
II If n = 3, l = 0, m = 0, for the last valence shell electron, then the possible atomic number must be 12 or 13.
III Total spin of electrons for the atom 25Mn is ± 7/2.
IV Spin magnetic moment of inert gas is 0

Options

A.I, II and III
B.II and III only
C.I and IV only
D.None of these

Solution

I : For n = 5, lmin = 0. ∴ Orbital angular momentum = = 0.(False)
II  : Outermost electronic configuration = 3s1 or 3s2. ∴ possible atomic number = 11or 12 (False).
III : Mn25 = [Ar] 3d5 4s2. ∴  5 unpaired electrons  ∴  Total spin = ± (False).
IV : Inert gases have no unpaired electrons.  ∴  spin magnetic moment = 0 (True).

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