Atomic StructureHard
Question
If first ionization potential of an atom is 16 V, then the first excitation potential will be :
Options
A.10.2 V
B.12 V
C.14 V
D.16 V
Solution
IP = 13.6Z2 = 16 (given).
1st excitation potential = 13.6 ×
× Z2 = 16 × 
= 12 V.
IP = 13.6Z2 = 16 (given).
1st excitation potential = 13.6 ×
× Z2 = 16 × = 12 V.IP = 13.6Z2 = 16 (given).
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