Progression (Sequence and Series)Hard
Question
If the angles A, B and C of a triangle are in an arithmetic progression and if a, b and c denote the lengths of the sides opposite to A, B and C respectively, then the value of the expression 
sin 2C + 
sin 2A is
sin 2C + sin 2A isOptions
A.
B.
C.1
D.√3
Solution
B = 60o
sin2C + 
sin2A = 2sinA cosC + 2sinCcosA
= 2sin(A + C) = 2sinB = 2 ×
sin2C + sin2A = 2sinA cosC + 2sinCcosA= 2sin(A + C) = 2sinB = 2 ×
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