JEE Advanced | 2013Introduction to 3DHard
Question
Perpendiculars are drawn from points on the line 
the plane x + y + z = 3. The feet of perpendiculars lie on the line
the plane x + y + z = 3. The feet of perpendiculars lie on the lineOptions
A.
B.
C.
D.
Solution
α = k + 2t - 2
β= k - t - 1
γ = k + 3t
α + β + γ = 3
Create a free account to view solution
View Solution FreeMore Introduction to 3D Questions
The equation of the planes passing through the line of intersection of the planes 3x − y − 4z = 0 and x + 3y...The equation of the plane which contains the lines and must be -...The distance between the parallel planes given by the equations, + 3 = 0 and + 5 = 0 is -...OABC is a tetrahedron whose vertices are O (0, 0, 0) ; A (a, 2, 3); B (1, b, 2) and C (2, 1, c) if its centroid is (1, 2...The point of intersection of the line and the plane 2x + 3y + z = 0 is -...