Set, Relation and FunctionHard
Question
Let p(x) be a function defined on R such that p′(x) = p′(1 - x), for all x ∈ [0, 1], p(0) = 1 and p(1) = 41. Then 
dx equals
dx equalsOptions
A.21
B.41
C.42
D.
Solution
p′(x) = p′(1 - x)
⇒ p(x) = - p(1 - x) + c
at x = 0
p(0) = - p (1) + c ⇒ 42 = c
now p(x) = - p(1 - x) + 42
⇒ p(x) + p(1 - x) = 42
2I =
⇒ I = 21
⇒ p(x) = - p(1 - x) + c
at x = 0
p(0) = - p (1) + c ⇒ 42 = c
now p(x) = - p(1 - x) + 42
⇒ p(x) + p(1 - x) = 42
2I =
⇒ I = 21Create a free account to view solution
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