Surface ChemistryHard
Question
Graph between log x/m and log p is a straight line inclined at an angle of 45o. When pressure is 0.5 atm and ln k = 0.693, the amount of solute adsorbed per gm of adsorbent will be :
Options
A.1
B.1.5
C.0.25
D.2.5
Solution
log 
= log k + 
log P
= tan 45o ln k = 0.69
n = 1 k = 2
= 2 x (0.5)1
x = 1
= log k + log P= tan 45o ln k = 0.69n = 1 k = 2
= 2 x (0.5)1x = 1
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