ElectrostaticsHard
Question
At distance of 5 cm and 10 cm outwards from the surface of a uniformly charged solid sphere, the potentials are 100 V and 75 V respectively. Then :
Options
A.potential at its surface is 150 V
B.the charge on the sphere is (5/3) × 10-10 C
C.the electric field on the surface is 1500 V/m
D.the electric potential at its centre is 225 V
Solution
Potential at 5 cm from surface =
= 100
Potential at 10 cm from surface =
= 75 ⇒ R = 10 cm
∴ Potential at surface =
= 150 V
Electric field on surface =
= 1500 V/m
Potential at 10 cm from surface =
∴ Potential at surface =
Electric field on surface =
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