Set, Relation and FunctionHard
Question
Consider the following relations:
R = {(x, y) | x, y are real numbers and x = wy for some rational number w};
S =
m, n, p and q are integers such that n, q ≠ 0 and qm = pn
. Then
R = {(x, y) | x, y are real numbers and x = wy for some rational number w};
S =
m, n, p and q are integers such that n, q ≠ 0 and qm = pn
. ThenOptions
A.neither R nor S is an equivalence relation
B.S is an equivalence relation but R is not an equivalence relation
C.R and S both are equivalence relations
D.R is an equivalence relation but S is not an equivalence relation
Solution
xRy need not implies yRx
S:
⇔ qm = pn
reflexive

⇒ qm = pn, ps = rq ⇒ ms = rn transitive.
S is an equivalence relation.
S:
⇔ qm = pn
reflexive

⇒ qm = pn, ps = rq ⇒ ms = rn transitive.S is an equivalence relation.
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
Let A be the set of all children in the world and R be a relation in A defined by x R y if x and y have same sex. Then R...Let {θ : sin θ - cosθ = √2 cos θ} and Q = {θ : sin θ + cosθ = √2 sinθ...The relation R defined in A = {1, 2, 3} by aRb if |a2 − b2| ≤ 5. Which of the following is false...A function f(x) satisfies the relation f(x + y) = f(x) + f(y) + xy (x + y) ∀, x, y, ∈ R. If f′(0) = - ...A function f(x) is such that f(x) = 0 has 8 distinct real roots and f(x) = f(6 - x) for x ∈ R. Sum of real roots o...