Surface ChemistryHard
Question
For the coagulation of 200 mL of As2S3 solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute needed for coagulation of 1 liter of solution) of NaCl.
Options
A.200
B.100
C.50
D.25
Solution
10 ml of 1 M NaCl contains NaCl = 10 × 1 = 10 milli mole
200 ml of As2S3 required NaCl for the coagulation = 10 milli mole
∴ 1000 ml of As2S3 required NaCl for the coagulation = 10 × 1000/200 = 50 milli mole
200 ml of As2S3 required NaCl for the coagulation = 10 milli mole
∴ 1000 ml of As2S3 required NaCl for the coagulation = 10 × 1000/200 = 50 milli mole
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