ElectrostaticsHard
Question
The diagram show a small bead of mass m carrying charge q. The bead can freely move on the smooth fused ring placed on a smooth horizontal plane. In the same plane a charge + Q has also been fixed as shown. The potential at the point A due to + Q is V. The velocity with which the bead could projected from the point A so that it can complete a circle should be greater than :
Options
A.
B.
C.
D.none of these
Solution
Given VA due to +Q is V, so VB = 4V
By energy conservation
mu2 + qV = 4qV
⇒ u =
By energy conservation
mu2 + qV = 4qV⇒ u =
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