ElectrostaticsMedium
Question
Potential at a point A is 3 volt and at a point B is 7 volt, as electron is moving towards A form B :
Options
A.It must have some K.E. at B to reach A
B.It need not have any K.E at B to reach A
C.To reach A it must have more than or equal to 4 eV KE at B
D.When it will reach A, it will have K.E more than or at least equal to 4 eV if it was released from rest at B
Solution
VA = 3 volt, VB = 7 volt
From energy conservation (Energy)A = (Energy)B
⇒ 1/2 mv2 - e × 7V = - e × 3V + 0
⇒ 1/2 mv2 = 4eV
From energy conservation (Energy)A = (Energy)B
⇒ 1/2 mv2 - e × 7V = - e × 3V + 0
⇒ 1/2 mv2 = 4eV
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