ElectrostaticsHard
Question
A charged cork of mass m suspended by light string is placed in uniform electric field of strength E = 
× 105NC-1 as shown in the figure. If in equilibrium position tension in the string is 
then angle ′α′with the vertical is :
× 105NC-1 as shown in the figure. If in equilibrium position tension in the string is then angle ′α′with the vertical is :Options
A.60o
B.30o
C.45o
D.18o
Solution
T sin α = qE cos 45o and Tcos α + qE sin 45o = mg
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