Trigonometric EquationHard
Question
Let cos(α + β) = 
and let sin(α - β) = 
, where 0 ≤ α, β ≤ 
, then tan 2α =
and let sin(α - β) = , where 0 ≤ α, β ≤ , then tan 2α = Options
A.
B.
C.
D.
Solution
cos (α + β) = 
⇒ tan( α + β) = 
sin (α - β) = ⇒ tan( α - β) = 
tan 2α = tan(α + β + α - β) =
⇒ tan( α + β) = sin (α - β) =
⇒ tan( α - β) = tan 2α = tan(α + β + α - β) =
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If cosec A + cot A = then tan A is equal to -...The number of solutions of |cos x| = sinx, 0 ≤ x ≤ 4π is-...The general solution of the trigonomrtirc equation sin x + cos x = 1 is diven by...The real value of θ for which the expression 1+i cosθ1-2i cosθ is a real number is (n ∈ I)Â...Equation of line in the plane π ≡ 2x - y + z - 4 = 0 which is perpendicular to the l whose equation is and wh...