Trigonometric EquationHard
Question
Let cos(α + β) =
and let sin(α - β) =
, where 0 ≤ α, β ≤
, then tan 2α =
and let sin(α - β) =
, where 0 ≤ α, β ≤
, then tan 2α = Options
A.

B.

C.

D.

Solution
cos (α + β) =
⇒ tan( α + β) =
sin (α - β) =
⇒ tan( α - β) =
tan 2α = tan(α + β + α - β) =
⇒ tan( α + β) =
sin (α - β) =
⇒ tan( α - β) =
tan 2α = tan(α + β + α - β) =

Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The sum of two forces is 18 N and resultant whose direction is at right angles to the smaller force is 12 N. The magnitu...If sin θ - cos θ = 0 and 0 < θ ≤ then θ is equal to-...The normal to the curve x = a(cosθ + θ sinθ), y = a( sinθ - θ cosθ) at any point ′&#...If 0 ≤ x ≤ 3π, 0 ≤ y ≤ 3π and cos x. sin y = 1 then the possible number of values of t...The period of sin2 θ is...