ElectrostaticsMedium
Question
A charge 3 coulomb experiences a force 300 N when placed in a uniform electric field. The potential difference between two points separated by a distance of 10 cm along the field line is :
Options
A.10 V
B.90 V
C.1000 V
D.1000 V
Solution
F = QE ⇒ 300 = 3 × E ⇒ E = 100 N/C
E =
⇒ᐃV = 100 × 
= 10 V
E =
⇒ᐃV = 100 × = 10 VCreate a free account to view solution
View Solution FreeMore Electrostatics Questions
A particle of mass 2g and charge 1μC is held at a distance of 1mC. if the particle is released it will be repelled....Mark out the correct options...Find the force experienced by the semicircular rod charged with a charge q, placed as shown in figure. Radius of the wir...Three dipoles each of dipole moment of magnitude p are placed tangentially on a circle of radius R in its plane position...The electric field produced by a positively charged particle, placed in an xy-plane is 7.2 (4î + 3ĵ) N/C at th...