ElectrostaticsHard
Question
A charge 3 coulomb experiences a force 300 N when placed in a uniform electric field. The potential difference between two points separated by a distance of 10 cm along the field line is :
Options
A.10 V
B.90 V
C.1000 V
D.1000 V
Solution
F = QE ⇒ 300 = 3 × E ⇒ E = 100 N/C
E =
⇒ᐃV = 100 × 
= 10 V
E =
⇒ᐃV = 100 × = 10 VCreate a free account to view solution
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