ElectrostaticsHard
Question
A charge 3 coulomb experiences a force 300 N when placed in a uniform electric field. The potential difference between two points separated by a distance of 10 cm along the field line is :
Options
A.10 V
B.90 V
C.1000 V
D.1000 V
Solution
F = QE ⇒ 300 = 3 × E ⇒ E = 100 N/C
E =
⇒ᐃV = 100 × 
= 10 V
E =
⇒ᐃV = 100 × = 10 VCreate a free account to view solution
View Solution FreeMore Electrostatics Questions
Due to an electric dipole shown in fig., the electric field intensity is parallel to dipole axis :...The given figure gives electric lines of force due to two charges q1 and q2. What are the signs of the two charges?...A semicircular ring of radius 0.5 m is uniformly charged with a total charge of 1.5 × 10-9 coul. The electric poten...As shown in the fig. charges + q and − q are placed at the vertices B and C of an isosceles triangle. The potentia...A sphere of radius R and charge Q is placed inside an imaginary sphere of radius 2R whose centre coincides with the give...