Solid StateHard

Question

A transition metal M can exist in two oxidation states +2 and +3. It forms an oxide whose experimental formula is given by MxO where x < 1.Then the ratio of metal ions in +3 state to those in +2 state is given by:

Options

A.(1 - x)/(1 + x)
B.1 + 2x
C.1 + x/2
D.2(1 - x) / (3x - 2)

Solution

   
⇒    Applying charge balance , 2y + 3(x - y) - 2 = 0
⇒   y = 3x - 2
∴ 

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