Momentum and CollisionHard
Question
Two blocks A and B each of mass m, are connected by a mass less spring of natural length L and spring of natural length L and spring constant k. The blocks are initially resting on a smooth horizontal floor with the spring at its natural length, the floor with a speed v along the line joining A and B and collides elastically with A. then : -


Options
A.the kinetic energy of the A-B system, at maximum compression of the spring, is zero
B.the kinetic energy of the A-B system, at maximum compression of the spring, is 
C.the maximum compression of the spring, is v 
D.the maximum compression of the spring, is v
Solution
At the time of maximum compression,
COLM : mu - 2mv (for A & B) ⇒ v = u/2
COME :
mu2 =
2mv2 +
kx2 ⇒ x = v
COLM : mu - 2mv (for A & B) ⇒ v = u/2
COME :
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A smooth sphere is moving on a horizontal surface with a velocity vector $(2\widehat{i} + 2\widehat{j})$ m/s immediately...The graph shows the extension of a wire of length 1m suspended form the top of a roof at one end and with a load W conne...A uniform bar of length 12 cm and mass $20m$ lies on a smooth horizontal table. Two point masses m and $2m$ are moving i...A homogeneous solid cylinder of length L (L < H/2), cross-sectional are A/5 is immersed such that it floats with its ...A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the disc...