Momentum and CollisionHard
Question
Two blocks A and B each of mass m, are connected by a mass less spring of natural length L and spring of natural length L and spring constant k. The blocks are initially resting on a smooth horizontal floor with the spring at its natural length, the floor with a speed v along the line joining A and B and collides elastically with A. then : -


Options
A.the kinetic energy of the A-B system, at maximum compression of the spring, is zero
B.the kinetic energy of the A-B system, at maximum compression of the spring, is 
C.the maximum compression of the spring, is v 
D.the maximum compression of the spring, is v
Solution
At the time of maximum compression,
COLM : mu - 2mv (for A & B) ⇒ v = u/2
COME :
mu2 =
2mv2 +
kx2 ⇒ x = v
COLM : mu - 2mv (for A & B) ⇒ v = u/2
COME :
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