Momentum and CollisionHard
Question
Two masses A and Of mass M and 2M respectively are connected by a compressed ideal spring. The system is placed on a horizontal frictional tables and a velocity 
in the z - direction as shown in the figure. The spring is released In the the subsequent motion the line from B to A always points along the î unit vector . At some instant of time mass B has a x - component of velocity as vxî. The velocity 
of mass A at that instant is
in the z - direction as shown in the figure. The spring is released In the the subsequent motion the line from B to A always points along the î unit vector . At some instant of time mass B has a x - component of velocity as vxî. The velocity of mass A at that instant is Options
A.vxî +
B.- vxî +
C.- 2vxî +
D.2vxî +
Solution
From COLM MvxA+ 2MvxB = 0 ⇒ vxA = - 2vxB
so
A = - 2vxî + v
so
A = - 2vxî + vCreate a free account to view solution
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