A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragment s scattere

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A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragment s scattered in the same horizontal plane. Three fragments are found to move with velocity v each as in the fig. The total energy released in the process of explosion

Accepted Answer

COLM &#8658; mv&#238; + mv&#309; + m + = 0 = - n Total energy released = mv2 + mv2 + mv2 + m = mv2(3 - &#8730;2)

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