Momentum and CollisionHard

Question

Two particles of mass m, constrained to move along the circumference of a smooth circular hoop of equal mass m, are initially located at opposite ends a diameter and given equal velocities v0 shown in the figure. The entire arrangement is located in gravity free space. Their velocity just before collision is 

Options

A.v0
B.v0
C.v0
D.v0

Solution


COLN ⇒ 2mv0 = 3mv1 ⇒ v1 = v0
COME ⇒ 2 × mv02 = 2 × m(v12 + v22) + mv12
⇒ 2m02 = 2m + 2mv22 + m
⇒ 2mv22 = 2v02 - 3 ⇒  v2 =
Velocity of particle = v0

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