Momentum and CollisionHard
Question
The figure shows the positions and velocities of two particles. If the particles move under the mutual attraction of each other, then the position of centre of mass at t = 1 s is
Options
A.x = 5m
B.x = 6m
C.x = 3m
D.x = 2m
Solution
vCM = 
= 1m/s
Position of centre of mass at t = 1s
XCM =
+ (1)(1) = 5 + 1 = 6m
= 1m/sPosition of centre of mass at t = 1s
XCM =
+ (1)(1) = 5 + 1 = 6mCreate a free account to view solution
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