Momentum and CollisionMedium
Question
Two masses m and are placed in fixed horizontal circular smooth hollow tube of radius r as shown. The mass m is moving with speed u and the mass 2m is stationary. After collision, the time elapsed for next collision. (Coefficient of restitution e =1/2)
Options
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Solution
Let the speed of balls m and 2m after collision be v1 and v2 as shown in figure. Applying conservation of momentum mv1 + 2mv2 = mu & - v1 + v2 = 
Solving we get and v2 = 
Hence the ball of mass m comes to rest and ball of mass 2m moves with speed 
. t = 
Solving we get and v2 = Hence the ball of mass m comes to rest and ball of mass 2m moves with speed . t = Create a free account to view solution
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