Momentum and CollisionMedium
Question
A small sphere of mass 1 kg is moving with a velocity (6î + ĵ) m/s. It hits a fixed smooth wall and rebounds with velocity (4î + ĵ) m/s. The coefficient of restitution between the sphere and the wall is -
Options
A.
B.
C.
D.
Solution
Impulse = Change in momentum = 1(4î + ĵ) - 1 (6î + ĵ) = - 2î
Which is perpendicular to the wall
Component of initial velocity along î = 6ĵ ⇒ Speed of approach = 6 m/s
Similarly speed of separation = 4ms-1 ⇒ e =
Which is perpendicular to the wall
Component of initial velocity along î = 6ĵ ⇒ Speed of approach = 6 m/s
Similarly speed of separation = 4ms-1 ⇒ e =
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