ProbabilityHard
Question
Sixteen players s1, s2 ....... , s16 play in a tournament. They are divided into eight pairs at random. From each pair a winner is decided on the basis of a game played between the two players of the pair. Assume that all the players are of equal strength. The probability that ′exactly one of the two players s1 & s2 is among the eight winners″ is -
Options
A.4/15
B.7/15
C.8/15
D.9/15
Solution
Total number of ways of selecting winners = 16C8
favourable ways = 2C1. 14C7 (out of s1 & s2 & rest )
so probability =
favourable ways = 2C1. 14C7 (out of s1 & s2 & rest )
so probability =
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