ProbabilityMedium
Question
Sixteen players s1, s2 ....... , s16 play in a tournament. They are divided into eight pairs at random. From each pair a winner is decided on the basis of a game played between the two players of the pair. Assume that all the players are of equal strength. The probability that ′exactly one of the two players s1 & s2 is among the eight winners″ is -
Options
A.4/15
B.7/15
C.8/15
D.9/15
Solution
Total number of ways of selecting winners = 16C8
favourable ways = 2C1. 14C7 (out of s1 & s2 & rest )
so probability =
favourable ways = 2C1. 14C7 (out of s1 & s2 & rest )
so probability =
Create a free account to view solution
View Solution FreeMore Probability Questions
Bag A contains 9 white and 8 black balls, while bag B contains 6 white and 4 black balls. One ball is randomly picked up...Two distinct numbers a and b are selected at random from $1,2,3,\ldots\ldots,50$. The probability, that their product ab...A bag contains $(N + 1)$ coins -N fair coins, and one coin with 'Head' on both sides. A coin is selected at random and t...If one card is drawn from a pack of card then the odds in favour of getting Ace is-...Cards are drawn one after another till an ace is obtained. The probability of not getting ace in first 26 cards is-...