ProbabilityMedium
Question
The probabilities of events, A ∩ B, A, B & A ∪ B are respectively in A. P. with probability of second term equal to the common difference. Therefore the events A and B are -
Options
A.compatible
B.independent
C.such that one of them must occur
D.such that one is twice as likely as the other
Solution
The probability of event
A ∩ B, B , B & A ∪ B are A.P.
P(B) - P(A) = P(A) - P(A ∩ B) = P(A) (Given)
P(B) = 2P(A); P(A ∩ B) = 0
A ∩ B, B , B & A ∪ B are A.P.
P(B) - P(A) = P(A) - P(A ∩ B) = P(A) (Given)
P(B) = 2P(A); P(A ∩ B) = 0
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