ProbabilityHard
Question
Two real numbers, x & y are selected at random. Given that 0 ≤ x ≤ 1 ; 0 ≤ y ≤ 1. Let A be the event that y2 ≤ x ; B be the event that x2 ≤ y, then -
Options
A.P(A ∩ B) = 1/3
B.P(A ∩ B) = 1/3
C.A & B are mutually exclusive
D.A & B are independent events.
Solution
0 ≤ x ≤ 1, 0 ≤ y ≤ 1
Let A be the event y2 ≤ x
B the event x2 ≤ y
total area = 1
P = (A ∩ B)
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