ProbabilityMedium
Question
Three numbers are chosen at random without replacement from {1, 2, 3, .....10}. The probability that the minimum of the chosen numbers is 3 or their maximum is 7 is -
Options
A.1/2
B.1/3
C.1/4
D.11/40
Solution
Selection of 3 no. having 3 as minimum is 6C2
selection of 3 no. having 7 as maximum is 7C2.
selection of 3 no. having 3 as minimum & 7 as maximum is 3C1.
n(A υ B) = n(A) + n(B) - n(A ∩ B)
= 6C2 + 7C2 - 3C1
sample space = 10C3
P(A) =
selection of 3 no. having 7 as maximum is 7C2.
selection of 3 no. having 3 as minimum & 7 as maximum is 3C1.
n(A υ B) = n(A) + n(B) - n(A ∩ B)
= 6C2 + 7C2 - 3C1
sample space = 10C3
P(A) =
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