Errors in measurementMedium
Question
In a vernier, N divisions of vernier scale coincide with (N - 1) divisions of main scale (in which 1 division) represents 1mm. The least count of the instrument in cm. should be
Options
A.N
B.N - 1
C.
D.
Solution
Least count =1 MSD - 1 VSD
(N - 1)MSD = N(VSD) ⇒ VSD =
MSD
Least count = 1MSD -
MSD
=
(1 mm) = 
cm
(N - 1)MSD = N(VSD) ⇒ VSD =
MSDLeast count = 1MSD -
MSD=
(1 mm) = cmCreate a free account to view solution
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