Vector 3DEasy
Question
The shortest distance between line y - x = 1 and curve x = y2 is
Options
A.

B.

C.

D.

Solution
P = (y2, y)
Perpendicular distance from P to x - y +1 = 0 is
y2 - y + 1 > 0 ∀ y ∈ R
∴ Coefficient y2 > 0
∴ Min value
Perpendicular distance from P to x - y +1 = 0 is
y2 - y + 1 > 0 ∀ y ∈ R
∴ Coefficient y2 > 0
∴ Min value

Create a free account to view solution
View Solution FreeMore Vector 3D Questions
The shortest distance between the line y - x = 1 and the curve x = y2 is...Shortest distance between the lines and is -...If the distances of the point $(1,2,a)$ from the line$\frac{x - 1}{1} = \frac{y}{2} = \frac{z - 1}{1}$ along the lines$L...If the shortest distance between the lines (α ≠ − 1) and x + y + z + 1 = 0 = 2x − y +z + 3 is, th...The shortest distance between the z-axis and the line x + y + 2z − 3 = 0 = 2x + 3y + 4z − 4, is :...