Nuclear Physics and RadioactivityHard
Question
An electron collides with a fixed hydrogen atom its ground in its ground state. Hydrogen atom gets existed and the colliding electron loses all its kinetic energy. Consequence the hydrogen atom may emit a photon corresponding to the largest wavelength of the Calmer series. The min. K.E of coiling electron will be -
Options
A.10.2eV
B.1.9 eV
C.12.1 eV
D.13.6 eV
Solution
Excitation up to n = 3 is required so that visible length is emitted upon de - excitation
So required energy = 13.6
= 13.1eV
So required energy = 13.6
= 13.1eVCreate a free account to view solution
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