Nuclear Physics and RadioactivityHard
Question
The decay constant of a ratio active substance is 0.173(years)-1. Therefore
Options
A.Nearly 63% of the radioactive substance will decay in (1/0.173)years
B.Half life of the ratio active substance is (1/0.173) years .
C.One - fourth of the radioactive substance will be left after nearly 8 years
D.All the above statements are true
Solution
λ = 0.173, N = Ne-λt
ᐃN = (N0 - N0e-λt) = Decayed amount
ᐃN = N0 (1 - 0.37) = N0 (0.63)
× 100 = 63 %
T1/2 =
= 4year
ᐃN = (N0 - N0e-λt) = Decayed amount
ᐃN = N0 (1 - 0.37) = N0 (0.63)
× 100 = 63 %T1/2 =
= 4yearCreate a free account to view solution
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