Nuclear Physics and RadioactivityHard

Question

The decay constant of a ratio active substance is 0.173(years)^-1. Therefore

Options

A.Nearly 63% of the radioactive substance will decay in (1/0.173)years

B.Half life of the ratio active substance is (1/0.173) years .

C.One - fourth of the radioactive substance will be left after nearly 8 years

D.All the above statements are true

Solution

λ = 0.173, N = Ne^-λt
ᐃN = (N₀ - N₀e^-λt) = Decayed amount
ᐃN = N₀ (1 - 0.37) = N₀ (0.63)
× 100 = 63 %
T_1/2 = = 4year

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