Nuclear Physics and RadioactivityHard
Question
In a Coolidge tube experiment, The Wavelength of the continuous X - ray spectrum is equal to 66.3 pm. Then
Options
A.electrons accelerate through potential difference of 12.75 kV in the Coolidge tube
B.electrons accelerate through potential difference of 18.75 kV in the Coolidge tube
C.de-Broglie wavelength of the electrons reaching the anti cathode is of the order of 10 μm
D.de-Broglie wavelength of the electrons reaching the anti cathode is of the order of 1.01 
Solution
V = 
× 10-10 volt
V =
volt = 
× 104 = 18.75 kV
× 10-10 voltV =
volt = × 104 = 18.75 kVCreate a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
The binding energies of nuclei X and Y are E1 and E2 respectively. Two atoms of X fuse to give one atom of Y and an ener...How many head - on elastic collisions must a neutron have with deuterium nuclei to reduce it energy from 6.561 MeV to 1 ...The number of photons (λ = 6630) that strike per second on a a totally reflecting screen (as screen in figure), so ...A radioactive nucleus decay as follows :- X X1 X2 X3 X4, if the atomic number and the mass number of X are 72 and 180 th...The order of magnitude of the density of a uranium nucleus is ($m_p = 1.67 \times 10^{-27}$ kg)...