Nuclear Physics and RadioactivityHard

Question

In a Coolidge tube experiment, The Wavelength of the continuous X - ray spectrum is equal to 66.3 pm. Then

Options

A.electrons accelerate through potential difference of 12.75 kV in the Coolidge tube
B.electrons accelerate through potential difference of 18.75 kV in the Coolidge tube
C.de-Broglie wavelength of the electrons reaching the anti cathode is of the order of 10 μm
D.de-Broglie wavelength of the electrons reaching the anti cathode is of the order of 1.01

Solution

V = × 10-10 volt
V = volt = × 104 = 18.75 kV

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