CircleMedium
Question
If θ is the angle between the asymptotes of the hyperbola 
= 1 with eccentricity e, then sec 
can be -
= 1 with eccentricity e, then sec can be - Options
A.e
B.e/2
C.e/3
D.
Solution
tan 
⇒ e2 - 1 = tan2 
⇒ sec 
= e
or e2 - 1 = cot2
⇒ cosec 
= e
⇒ sec
= 
⇒ e2 - 1 = tan2 ⇒ sec = eor e2 - 1 = cot2
⇒ cosec = e⇒ sec
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