HyperbolaHard
Question
The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0) The possible equation of the hyperbola is -
Options
A.
= 1
= 1B.
= 1
= 1C.
= 1
= 1D.
= 1
= 1Solution
Centre of hyperbola is (5, 0), so equation is
a = 5, ae - a = 8 ⇒ e =
b2 = 144.
So equation is
= 1
Centre of hyperbola is (5, 0), so equation is
a = 5, ae - a = 8 ⇒ e =
b2 = 144.
So equation is = 1
a = 5, ae - a = 8 ⇒ e =
b2 = 144.
So equation is
= 1Centre of hyperbola is (5, 0), so equation is
a = 5, ae - a = 8 ⇒ e =
b2 = 144.
So equation is
= 1Create a free account to view solution
View Solution FreeMore Hyperbola Questions
If the normal to the rectangular hyperbola xy = c2 at the point ′t′ meets the curve again at ′t1′...If the focii of the ellipse = 1 and the hyperbola = 1 coincides then value of k =...The equation = 1, k > 1 represents-...Let the domain of the function $f(x) = \log_{3}\log_{5}\log_{7}$ ( $9x - x^{2} - 13$ ) be the interval ( $m,n$ ). Let th...The point (at2, 2bt) lies on the hyperbola = 1 for...