HyperbolaHard
Question
The locus of the point of intersection of the lines √3x - y - 4 √3k = 0 and √3kx + ky - 4 √3 = 0 for different values of k is -
Options
A.ellipse
B.parabola
C.circle
D.hyperbola
Solution
Let point of intersection is (x1, y1).
So. √3 x1 - y1 = 4 √3 K ... (i)
√3 K x1 + Ky1 = 4 √3 ... (ii)
Multiply (i) and (ii), we get 3x12 - y12 = 48.
So. √3 x1 - y1 = 4 √3 K ... (i)
√3 K x1 + Ky1 = 4 √3 ... (ii)
Multiply (i) and (ii), we get 3x12 - y12 = 48.
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