CircleHard

Question

The normal at a variable point P on an ellipse = 1 of eccentricity e meets the axes of the ellipse in Q and R then the locus of the mid-point of QR is a conic with an eccentricity e′ such that -

Options

A.e′ is independent of e
B.e′ = 1
C.e′ = e
D.e′ = 1/e

Solution

Eqution of normal at P is
axsec θ - by cosec θ = a2 - b2        ...... (i)
Q ≡       ,R ≡
Let middle point of QR be S(h, k).
2h = . cosθ ; 2k = - . sinθ
2h = ae2cosθ   k = - sin θ
cos θ =  .... (ii)        sinθ =     ..... (iii)
Square & add (ii) & (iii),
= 1
⇒    = 1    ⇒  = 1
where, A = &     B =
B > A
e′ = 1 - = 1 -
= 1 - = e2 ⇒ e′ = e

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